PLEASE HELP:How do I solve this:If james goes 15 miles faster per hour, he will go 260 miles in 20 minutes less than normal. What is the original rate?
Accepted Solution
A:
15 mi/h= 15mi/60 min= 1/4 (mi/min)
x is original speed (mi/min) t is original time x*t =260
(x+1/4)=5x/4 is new speed t-20 - new time (x+1/4)(t-20)=260
Check 260/100=2.6h time with old speed 260/(115)=2.26 h time with new speed 2.6-2.26 = 0.34 h difference between old and new time 0.34h*60min/1h≈20 min difference between old and new time in minutes